How do you rearrange a quartic equation in the form of #ax^6 + bx^5+cx^4+dx^3+ex^2+fx+g# to vertex form (If possible)?

1 Answer
Jul 7, 2018

A few observations...

Explanation:

An equation is an expression that equates one thing to another, so would have to contain an equals sign somewhere.

The expression you have specified is a sextic (i.e. degree #6#) polynomial and not a quartic (i.e. degree #4#).

It can be understood to describe a function of #x#.

Its graph can have a total of #5# vertices, so it is not clear what you would mean by "vertex form" for a sextic.

An example would be the sextic Chebyshev polynomial of the first kind:

#T_6(x) = 32x^6-48x^4+18x^2-1#

graph{32x^6-48x^4+18x^2-1 [-2.5, 2.5, -1.25, 1.25]}