How do you solve #5x-3y= 8# and #-6x+y=20# using substitution?

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Answer 1 · 2018-07-09T22:51:24

#x=-68/13# & #y=-148/13#

Given equations:

#5x-3y=8\ .........(1)#

#-6x+y=20\ ...........(2)#

Substituting #y=6x+20# from (2) into (1), we get

#5x-3(6x+20)=8#

#-13x-60=8#

#-13x=68#

#x=-68/13#

Substituting #x=-68/13# in (2), we get

#y=6x+20#

#=6(-68/13)+20#

#=-\frac{148}{13}#