Ming has 15 quarters, 30 dimes, and 48 money so nickels. He wants to group his so that each group has the same number of each coin. What is the greatest number of groups he can make?

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Answer 1 · 2018-07-11T19:15:24

3 groups of of 31 coins 5 quarters, 10 dimes and 16 nickels in each group.

The greatest common factor (GCF) for the values, 15, 30 and 48 is the number 3.

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That means the coins can be divided equally into three groups.

#15/3 = 5# quarters

#30/3 = 10# dimes

#48/3 = 16# nickels

#5 + 10 + 16 = 31# coins