How do you find the relative extrema for #f(x) = (x+2)/x#? Calculus Graphing with the First Derivative Classifying Critical Points and Extreme Values for a Function 1 Answer Sonnhard Jul 12, 2018 No relative extrema Explanation: Writing #f(x)=(x+2)/x=1+2/x# so #f'(x)=-2/x^2# and #f'(x)=-2/x^2# is #ne 0# Answer link Related questions How do you find and classify the critical points of #f(x)=x^3#? How do you find the critical points of a rational function? How do you know how many critical points a function has? How many critical points can a cubic function have? How many critical points can a function have? How many critical points can a quadratic polynomial function have? What is the first step to finding the critical points of a function? How do you find the absolute extreme values of a function on an interval? How do you find the extreme values of the function and where they occur? What is the extreme value of a quadratic function? See all questions in Classifying Critical Points and Extreme Values for a Function Impact of this question 2012 views around the world You can reuse this answer Creative Commons License