How do you solve #5x+8y=28# and #-8+y=38# using substitution?
1 Answer
Jul 12, 2018
Explanation:
#5x+8y=28to(1)#
#-8+y=38to(2)#
#"simplify equation "(2)" by adding 8 to both sides"#
#y=38+8=46#
#"substitute "y=46" into equation "(1)#
#5x+(8xx46)=28#
#5x+368=28#
#"subtract 368 from both sides"#
#5x=28-368=-340#
#"divide both sides by 5"#
#x=(-340)/5=-68#
#"solution is "(x,y)to(-68,46)#
