How do you transform #f(x)=sqrt (x)# into # g(x)=4*sqrt(3(x-1))+8# ?
1 Answer
Jul 13, 2018
Please see the explanation below
Explanation:
To transform from
to
The
graph{(y-sqrtx)(y-sqrtx-8)=0 [-10, 10, -5, 5]}
The
graph{(y-sqrtx)(y-4sqrtx)=0 [-16.24, 29.37, -4.55, 18.27]}
The
graph{(y-sqrtx)(y-sqrt(3x))=0 [-16.24, 29.37, -4.55, 18.27]}
The
graph{(y-sqrt(x))(y-sqrt(x-1))=0 [-9.45, 22.58, -1.15, 14.88]}
And alltogether
graph{(y-sqrtx)(y-4sqrt(3(x-1))-8)=0 [-19.08, 32.23, -5.97, 19.7]}