What volume is occupied by 1.5 moles of oxygen, #O_2#, gas at STP?

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Answer 1 · 2018-07-13T10:29:23

# 33.6# liters

The molar volume of an ideal gas at STP is 22.4 liters/mole

# 1.5 xx 22.4 = 33.6 #

Answer 2 · 2018-07-13T10:49:57

#"Volume Occupied" = 33.6dm^3#

Let the volume occupied be represented by #x#

Since #1.5# moles of #O_2# gas yield #xdm^3# of #O_2# gas

Therefore;

#(2 xx 16)gmol^-1# of #O_2# gas will produce #22.4dm^3# of #O_2# gas

#1# of #O_2# gas will produce #22.4dm^3# of #O_2# gas

#1.5 -> x#

#1 -> 22.4#

Cross multiplying;

#x xx 1 = 1.5 xx 22.4#

#x = 33.6#

Hence;

#"Volume Occupied" = 33.6dm^3#