A triangle has corners at #(3, 1 )#, #( 2, 3 )#, and #( 2 , 6 )#. If the triangle is dilated by # 1/5 x# around #(1, 1)#, what will the new coordinates of its corners be?

1 Answer
sankarankalyanam
Jul 14, 2018

#color(indigo)("New coordinates are " (7/5,1), (6/5,7/5), (6/5,2)#

Explanation:

#A(3,1), B(2,3), C(2,6), " about point " D (1,1), " dilation factor "1/5#

#A'((x),(y)) =(1/5)a - (-4/5)d =(1/5)*((3),(1)) - (-4/5)*((1),(1)) = ((7/5),(1))#

#B'((x),(y)) = (1/5)b - (-4/5)d = (1/5)*((2),(3)) - (-4/5)*((1),(1)) = ((6/5),(7/5))#

#C'((x),(y)) = (1/5)c - (-4/5)d = (1/5)*((2),(6)) - (-4/5)*((1),(1)) = ((6/5),(2))#

#color(indigo)("New coordinates are " (7/5,1), (6/5,7/5), (6/5,2)#

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