How do you solve #5x-12=2x+6#?

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Answer 1 · 2018-07-14T17:59:19

#x = 6#

#5x - 12 = 2x + 6#

First, subtract #color(blue)(2x)# from both sides of the equation:
#5x - 12 quadcolor(blue)(-quad2x) = 2x + 6 quadcolor(blue)(-quad2x)#

#3x - 12 = 6#

Now add #color(blue)12# to both sides;
#3x - 12 quadcolor(blue)(+quad12) = 6 quadcolor(blue)(+quad12)#

#3x = 18#

Finally, divide both sides by #color(blue)3#:
#(3x)/color(blue)3 = 18/color(blue)3#

Therefore,
#x = 6#

Hope this helps!