How do you solve $y+(-10)=6$ ?

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Answer 1 · 2018-07-14T18:09:40

$y = 16$

$y + (-10) = 6$

Adding a negative number is the same thing without the positive sign. Therefore, the equation becomes:
$y - 10 = 6$

Now add $color(blue)10$ to both sides:
$y - 10 quadcolor(blue)(+quad10) = 6 quadcolor(blue)(+quad10)$

Therefore,
$y = 16$

Hope this helps!

How do you solve y+(-10)=6y+(-10)=6?