How do you solve #4a - 9\leq - 25#?
1 Answer
Jul 14, 2018
Explanation:
#"isolate "4a" by adding 9 to both sides"#
#4a<= -25+9#
#4a<=-16#
#"divide both sides by 4"#
#a<=-4#
#x in(-oo,-4]larrcolor(blue)"in interval notation"#
