Question

What is the equation of the line that passes through `(-2,1)` and is perpendicular to the line that passes through the following points: #(-3,6),(7,-3)?

Answer 1

`9y-10x-29=0`

Explanation:

Gradient of `(-3,6)` and `(7,-3)`
`m_1=(6--3)/(-3-7)=9/-10`

For perpendicular lines, `m_1m_2=-1`
so `m_2=10/9`

Using the point gradient formula,
`(y-1)=10/9(x+2)`

`9y-9=10x+20`

`9y-10x-29=0`