Someone who solves it by reduction method ?:(

#3x - 7y = 38#
#7x + 4y = 48#

1 Answer
Jul 19, 2018

#x=8" "# and #" "y=-2#

Explanation:

Given:

#{ (3x - 7y = 38), (7x + 4y = 48) :}#

Multiply the first equation by #4# and the second by #7# so that the coefficients of #y# will cancel:

#{ (12x - 28y = 152), (49x + 28y = 336) :}#

Then adding the two equations, we find:

#61x = 488#

Dividing both sides by #61#, we find;

#x = 8#

Going back to the original equations, we could substitute this value for #x# into one of them and hence find #y#, but instead let us multiply the first equation by #7# and the second by #3#, to make the coefficients of #x# cancellable:

#{ (21x - 49y = 266), (21x + 12y = 144) :}#

Subtracting the first of these equations from the second, we find:

#61y = -122#

Then dividing both sides by #61#, we find:

#y = -2#