(1/1-sinx)-(sinx/1+sinx);tanx Rewrite?

1 Answer
Hriman
Jul 19, 2018

#1+2tan^2x#

Explanation:

#(1/(1-sinx))-(sinx/(1+sinx))#

#((1+sinx)/((1-sinx)(1+sinx)))-((sinx(1-sinx))/((1+sinx)(1-sinx)))#

#((1+sinx)/(1-sin^2x))-((sinx-sin^2x)/(1-sin^2x))#

#(1+sin^2x)/(1-sin^2x)#

#(1+sin^2x)/(cos^2x)#

#1/cos^2x+(sin^2x)/(cos^2x)#

#sec^2x+tan^2x#

#1+tan^2x+tan^2x#

#1+2tan^2x#

Related questions
Impact of this question
1336 views around the world
You can reuse this answer
Creative Commons License