How do you find the critical points for #f(x)=-x^2+6x+2#?

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Answer 1 · 2018-07-19T18:41:20

#x=3#

Given polynomial function:

#f(x)=-x^2+6x+2#

#f'(x)=-2x+6#

#f''(x)=-2#

for critical (minima or maxima) points #f'(x)=0#, hence

#-2x+6=0#

#x=6/2#

#x=3#

since #f''(x)=-2<0# hence the function is maximum at #x=3#