Question

Factorise of the following `16abc-8ab^2+24bc`?

Answer 1

`16abc-8ab^2+24bc = 8b(2ac-ab+3c)`

Explanation:

Given:

`16abc-8ab^2+24bc`

Note that each of the terms is divisible by both `8` and `b`, so by `8b`...

`16abc-8ab^2+24bc = 8b(2ac)-8b(ab)+8b(3c) = 8b(2ac-ab+3c)`

The remaining trinomial cannot be factored further.