What is #(2h^4-h^3+h^2 +h-3)-:(h^2- 1)#?

Question

2425 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-22T04:40:12

#(2h^4-h^3+h^2 +h-3)-:(h^2- 1)#

#=(2h^4-h^3+h^2 +h-3)/(h^2- 1)#

#=(2h^4-2h^2-h^3 +h+3h^2-3)/(h^2- 1)#

#=(2h^2(h^2-1)-h(h^2-1)+3(h^2-1))/(h^2- 1)#

#=((h^2-1)(2h^2-h+3))/(h^2- 1)#

#=((cancel(h^2-1))(2h^2-h+3))/(cancel(h^2- 1))#

#=2h^2-h+3#