What are the critical values, if any, of #f(x) = 2x^4 - 4x^2 +6 #?

1 Answer
Jul 23, 2018

critical values at #x = 0, x = +- 1#

Explanation:

Given: #f(x) = 2x^4 - 4x^2 + 6#

Find the first derivative:

#f'(x) = 8x^3 - 8x#

Find critical values by factoring and setting #f'(x) = 0#:

#f'(x) = 8x^3 - 8x = 8x(x^2 - 1) = 8x (x+1)(x-1) = 0#

critical values at #x = 0, x = +- 1#

Graph of #f(x) = 2x^4 - 4x^2 + 6#:

graph{2x^4 - 4x^2 + 6 [-5, 5, -2, 10]}