If a heater with power 1000 W gives #3.6*10^6# heat energy in 1 hour. What will be the temperature raised in 50kg of water with temperature #30^@#C by that heat?

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Answer 1 · 2018-07-23T21:16:51

#t_f=47.2^@C#

Let's say I didn't know the units on #3.6*10^6#, I can prove that the units have to be #J#

A watt is a #J/s#

#(1000J)/s*(3600s)/(1hr)= 3.6*10^6 J/(hr)#

#q=mcDeltat#

#3.6*10^6 J= 50,000g*4.184 J/(g^@C)*(t_f-30^@C)#

#3.6*10^6 J= 209,200 J/(C)t_f-6.276*10^6J#

#(9.876*10^6J)/(209200J/C)= t_f#

#t_f=47.2^@C#