What is the error in the proof? (more in details)

Assignment

1 Answer
Jul 24, 2018

Dividing #0# by #0# is indeterminable

Explanation:

The error in the proof results when you divide: #(x+y-z)# by #(x+y-z)#, it should work in any case but one, and here that it is the case:

#x+y-z=0#

And dividing #0# by #0# is indeterminable

#11(0)=10(0)# #-># this is true

Until you divide #0# by #0#