How do you graph #y=-tan(x-pi/2)#?

1 Answer
A. S. Adikesavan
Jul 24, 2018

See graph, with asymptotes.

Explanation:

# y = - tan ( x - pi/2 ) = -(-tan ( pi/2 - x )) = cot x#,

asymptotic # x ne kpi, k = 0, +- 1, +-2, +-3, ...#

Graph of #y = - tan ( x = pi/2 )#, with asymptotes

graph{(y sin x - cos x)(x+0.001y)(x^2- (pi)^2+0.001y)(x^2-(2pi)^2+0.001y) = 0} :

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