How do you solve #20x + 19= 10x + 13#?

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Answer 1 · 2018-07-25T01:19:18

#x = -3/5#

#20x + 19 = 10x + 13#

Subtract #color(blue)(10x)# from both sides:
#20x + 19 quadcolor(blue)(-quad10x) = 10x + 13 quadcolor(blue)(-quad10x)#

#10x + 19 = 13#

Subtract #color(blue)(19)# from both sides:
#10x + 19 quadcolor(blue)(-quad19) = 13 quadcolor(blue)(-quad19)#

#10x = -6#

Divide both sides by #color(blue)(10)#:
#(10x)/color(blue)10 = (-6)/color(blue)10#

#x = -6/10#

#x = -3/5#

Hope this helps!

Answer 2 · 2018-07-25T03:58:29

#x=-3/5#

Let's get our #x# terms on one side. We can start by subtracting #10x# from both sides to get

#10x+19=13#

Next, let's get our constants on the right. We can subtract #19# from both sides to get

#10x=-6#

Dividing both sides by #10#, we get

#x=-6/10# or #x=-3/5#

Hope this helps!