What is #sqrt2( 5 - sqrt2) ?#

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Answer 1 · 2018-07-26T19:05:54

#5\sqrt2-2#

Given that

#\sqrt2(5-\sqrt2)#

#=\sqrt2\cdot 5-\sqrt2\cdot \sqrt2#

#=5\sqrt2-2#

Answer 2 · 2018-07-26T22:58:03

#5sqrt2-2#

We can distribute #sqrt2# to both of the terms in the parenthesis. Recall that #sqrt2*sqrt2=2#. We now have

#5sqrt2-2#

Hope this helps!