#(d-2)/4 = (d-1)/3# Solve?
2 Answers
Jul 27, 2018
Explanation:
Given equation:
Jul 27, 2018
Explanation:
#"multiply both sides by the lowest common multiple"#
#"of 4 and 3 which is 12"#
#cancel(12)^3(d-2)/cancel(4)^1=cancel(12)^4(d-1)/cancel(3)^1#
#3(d-2)=4(d-1)larrcolor(blue)"distribute both sides"#
#3d-6=4d-4#
#"subtract "4d" from both sides"#
#3d-4d-6=-4#
#-d-6=-4#
#"add 6 to both sides"#
#-d=-4+6#
#-d=2rArrd=-2#