Question

How do you solve `4( 2- 5x ) = 6- 3( 1- 3x )`?

Answer 1

`x=5/29`

Explanation:

`4(2-5x)=6-3(1-3x)`

Expand the brackets
`8-20x=6-(3-9x)`

`8-20x=6-3+9x`

Simplify
`8-20x=3+9x`

Move the `x` onto one side
`29x=5`

Divide both sides by `29`
`x=5/29`

Answer 2

`x=5/29`

Explanation:

We can distribute the `4` on the left side, and the `-3` on the right. Doing this, we now have

`8-20x=6-3+9x`

We can combine like terms to get

`8-20x=3+9x`

Let's get our constants on one side by subtracting `8` from both sides:

`-20x=-5+9x`

Next, subtract `9x` from both sides to get

`-29x=-5`

Lastly, we can divide both sides by `-29` to get

`x=5/29`

Hope this helps!