How do you simplify #(2-3i)+(-2-5i)#?

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Answer 1 · 2018-07-28T04:20:01

#-8i#

Given that

#(2-3i)+(-2-5i)#

#=2-3i-2-5i#

#=-8i#

Answer 2 · 2018-07-28T06:10:18

#-8i#

Even though it is not a variable, for the most part, we can treat the imaginary unit like it is one.

Since we aren't multiplying by a negative, the parenthesis are unnecessary. We simply just add the corresponding parts to get

#-8i#, as #2# and #-2# cancel out.

Hope this helps!