How do you find the slope & equation of tangent line to f(x)=-1/x at (3,-1/3)?
2 Answers
Jul 28, 2018
Slope
Explanation:
Given function:
Now, the slope
Now, the equation of tangent at the point
Jul 28, 2018
Explanation:
"the slope of the tangent line is "f'(x)" at "x=3
f(x)=-1/x=-x^-1
f'(x)=x^-2=1/x^2
f'(3)=1/(3^2)=1/9
y+1/3=1/9(x-3)
y+1/3=1/9x-1/3
y=1/9x-10/3