How do you solve #4^(2p)=4^(-2p-1)#?

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Answer 1 · 2018-07-28T17:44:31

#p=-1/4#

Given equation

#4^{2p}=4^{-2p-1}#

Comparing the powers on base #4# we get

#2p=-2p-1#

#2p+2p=-1#

#4p=-1#

#p=-1/4#

Answer 2 · 2018-07-28T18:45:39

#p=-1/4#

#"since both sides are expressed in base 4"#

#"we can equate the exponents"#

#2p=-2p-1#

#4p=-1rArrp=-1/4#

Answer 3 · 2018-07-28T19:25:27

#p=-1/4#

Since the bases are the same, we can equate the exponents. With this in mind, we now have:

#2p=-2p-1#

Next, let's add #2p# to both sides to get

#4p=-1#

Lastly, we can divide both sides by #4# to get

#p=-1/4#

Hope this helps!