A certain gas has a volume of 500.0 mL at 77.0C and 600.0 torr. Calculate the temperature, C, if the volume decreased to 400.0 mL an the pressure is increased to 1.00 atm.? (81.9 C)

combined gas law

1 Answer
anor277
Jul 30, 2018

Well, we know #(P_1V_1)/T_1=(P_2V_2)/T_2#

Explanation:

And units of absolute temperature are specified...

We solve for #T_2=(P_2V_2)/(P_1V_1)xxT_1#...we also apprehend that #760*mm*Hg-=1*atm#, or rather that #1*atm# pressure will support a column of mercury #760*mm# high. The pressure units cancel out here...

#T_2=(1*atmxx400*mL)/((600*mm*Hg)/(760*mm*Hg*atm^-1)xx500*mL)xx350*K=??*K#

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