How do you solve this set of linear equations: $d+ q = 14; 0.10d + 0.25q = 4.55$ ?

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Answer 1 · 2018-07-30T11:47:36

$d=-7$ and $q=21$

$20*(0.10d+0.25q)-2*(d+q)=20*4.55-2*14$

$2d+5q-2d-2q=91-28$

$3q=63$

So, $q=63/3=21$

Thus, $d=14-q=14-21=-7$

How do you solve this set of linear equations: d+ q = 14; 0.10d + 0.25q = 4.55d+ q = 14; 0.10d + 0.25q = 4.55?