Hot water of mass 10 kg at 90°C is cooled forr taking bath by mixing 20kg of water at 20°C. What will be the final temperature of the water neglecting the heat taken by bucket ?

1 Answer
Aug 1, 2018

Let the final temperature of the mixture be t^@C

Equating the heat loss and heat gained we get

20xx4.2xx(t-20)=10xx4.2xx(90-t)

=>20t-400=900-10t

=>30t=1300

=>t=43.3^@C