Question

How can you find 2 zeros of this equation `y^2-5y+6=0`?

Answer 1

`y=3" or "y=2`

Explanation:

`"factor the quadratic and solve for y"`

`"the factors of "+6" which sum to "-5"`

`"are "-2" and "-3`

`(y-2)(y-3)=0`

`"equate each factor to zero and solve for y"`

`y-2=0rArry=2`

`y=3=0rArry=3`
graph{x^2-5x+6 [-10, 10, -5, 5]}