How many grams of Kr are in a 2.74 L cylinder at 58.7 °C and 2.99 atm?

1 Answer
anor277
Aug 3, 2018

I get a mass of approx. #25*g#...

Explanation:

We use the old Ideal Gas equation...

#n=(PV)/(RT)=(2.99*atmxx2.74*L)/(0.0821*(L*atm)/(K*mol)*331.9*K)#

#=0.301*mol#...

And we know (how) that krypton has a molar mass of #83.8*g*mol^-1#...

And so we take the product...…..

#0.301*molxx83.8*g*mol^-1=??*g#

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