Question

How do you evaluate `5x+11\times 2=16x-26`?

Answer 1

`x=48/11`

Explanation:

First simplify the expression on each side of the equation

`5x+11*2=16x-26`

`5x + 22 = 16x-26`

Group like terms. When a term is moved to the other side of an equation, the sign changes.

`22+26=16x-5x`

`48=11x`

Divide both sides by 11 so that `x` stands alone

`(cancel(11)x)/cancel(11)=48/11`

`x=48/11`

Answer 2

`x=48/11`

Explanation:

This simplifies to

`5x+22=16x-26`

To make this easier, I'll switch the sides. I didn't do any math here, I only switched the sides:

`16x-26=5x+22`

We can add `26` to both sides to get

`16x=5x+48`

Next, to get our `x` terms on one side, let's subtract `5x` from both sides to get

`11x=48`

To completely isolate `x`, we can divide both sides by `11` to get

`x=48/11`

Hope this helps!