How do you solve #5x - 40= 2( 5x - 10)#?

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Answer 1 · 2016-10-31T14:16:13

#x = -4#

First expand what is in parenthesis and then solve for #x# while keeping the equation balanced:

#5x - 40 = 10x - 20#

#5x - 40 - 5x + 20 = 10x - 20 - 5x + 20#

#-20 = 5x#

#(5x)/5 = (-20)/5#

#x = -4#

Answer 2 · 2018-08-05T01:57:23

#x=-4#

To make it easier, first I will switch the sides:

#2(5x-10)=5x-40#

We can start by distributing the #2# on the left to get

#10x-20=5x-40#

Next, we can add #20# to both sides to get

#10x=5x-20#

Next, let's get our variables on one side by subtracting #5x# from both sides:

#5x=-20#

Lastly, we can divide both sides by #5# to get

#x=-4#

Hope this helps!