Question

How do you evaluate `e^ln3`?

Answer 1

Try to write it as a log:
`ln(x)=ln3` which is: `x=e^(ln(3))`
But to have:
`ln(x)=ln3` means that `x=3` or: `e^(ln(3))=3`

Answer 2

`3`

Explanation:

Since base-`e` and natural log (`ln`) are inverses, they cancel, and we're left with

`cancele^(cancel(ln)3)=3`

Hope this helps!