Let the number of digits of 22005 be x and that of 52005 be y then the possible value of x+y=?
1 Answer
Aug 5, 2018
Explanation:
Note that "number of digits" of
So:
x=⌊log1022005⌋+1=⌊2005log102⌋+1
y=⌊log1052005⌋+1
y=⌊2005log105⌋+1
y=⌊2005(1−log102)⌋+1
y=⌊−2005(log102)⌋+2006
y=−⌈2005log102⌉+2006
So:
x+y=⌊2005log102⌋−⌈2005log102⌉+2006=2005