Question

What is 'x' in 4=(1)/(1-3x)?

`4=(1)/(1-3x)`

Answer 1

`x=1/4`

Explanation:

`4=1/(1-3x)`

Multiply both sides by `(1-3x):`

`4(1-3x)=(1cancel(1-3x))/cancel(1-3x)`

Distribute `4` through on the left:

`4-(4)(3x)=1`

`4-12x=1`

Subtract `4` from each side:

`cancel(4-4)-12x=1-4`

`-12x=-3`

Divide each side by `-12:`

`(cancel(-12)x)/cancel(-12)=(-3)/(-12)`

`x=(cancel-3)/(cancel-12)=3/12=1/4`

Answer 2

`x=1/4`

Explanation:

To get rid of the variable in the denominator, we can multiply both sides by `1-3x` to get

`4(1-3x)=1`

Next, we can distribute the `4` on the left to get

`-12x+4=1`

Next, subtract `4` from both sides to get the constants on the right.

`-12x=-3`

Lastly, we divide both sides by `-12` to isolate the variable. We get

`x=1/4`

Hope this helps!