The overall reaction in the body is described by the equation C6H12O6(aq) + 6O2(g) = 6CO2(g) + 6H2O(l). How many grams of oxygen are required to convert 23.0 g of glucose to CO2 and H2O? What is the number of g of CO2 produced?

1 Answer
anor277
Aug 8, 2018

Approx. #25*g# with respect to oxygen...

Explanation:

You have the stoichiometric equation...

#C_6H_12O_6(g) +6O_2(g) rarr 6CO_2(g) + 6H_2O(l)#

And the normal rigmarole in these reactions, is to balance the carbons as carbon dioxide, then balance the hydrogens as water, and THEN balance the oxygens.

And thus #180*g# of glucose is oxidized by #192*g# dioxygen to give #264*g# carbon dioxide, and #108*g# water...

With respect to glucose we have a molar quantity of...

#n_"glucose"=(23.0*g)/(180.16*g*mol^-1)=0.128*mol#

And thus SIX EQUIV dioxygen are required...

#"mass"_"dioxygen"=0.128*molxx6xx32.00*g*mol^-1=24.5*g#

And thus SIX EQUIV carbon dioxide are released...

#"mass"_"carbon dioxide"=0.128*molxx6xx44.01*g*mol^-1=??*g#

Related questions
Impact of this question
8226 views around the world
You can reuse this answer
Creative Commons License