Prove #lim_(xrarr5)(2x+4)=14#?

1 Answer
Aug 8, 2018

We can prove this in a number of ways. Since this is classified as pre-calculus, I will avoid an #epsilon - delta# proof.

In general, a limit is the value that a function approaches. Let
#f(x) = 2x+4#.

First, let's just justify it numerically.

If we plug in values just barely less than #x=5#, we see that the values approach 14, i.e.
#f(4) = 12 #
#f(4.9) = 13.8#
#f(4.99) = 13.98#
#f(4.999) = 13.998#
and so on and so forth

The same applies if we plug in values just barely above #x=4#:
#f(6) = 16 #
#f(5.1) = 14.2#
#f(5.01) = 14.02#
#f(5.001) = 14.002#

This means that as #x rightarrow 5#, the function approaches 14.

Now, we can also sort of prove this limit:

For a function that is "simple", such as this line, we can actually just plug in the value and get our answer, too.

#f(5) = 2 * 5 + 4 = 14#