Find the the digits of number x that satisfy the mutiply of all digits of x equal to x^2-10x-22?

1 Answer
Aug 8, 2018

#x=49+5i, 49-5i#
2 solutions

Explanation:

I'm pretty sure you are asking for the possible solutions

#x^2-10x-22#

I would use the quadratic formula:
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#x=(10+sqrt(-10^2)-(4*1*-22))/(2*1)#

#x=(10+10i+88)/2#

#x=49+5i#

#x=(10-sqrt(-10^2)-(4*1*-22))/(2*1)#

#x=(10-10i+88)/2#

#x=49-5i#