How do you solve #\frac { 1} { 2} ( 1+ \frac { 1} { x } ) - 2= \frac { 1- x } { x }#?

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Answer 1 · 2018-08-10T20:41:09

#x=-1#

Here,

#1/2(1+1/x)-2=1/x-1#

#=>1/2(1+1/x)-2-1/x+1=0#

#=>1/2(1+1/x)-1-1/x=0#

#=>1/2(1+1/x)-(1+1/x)=0#

#=>(1+1/x)[1/2-1]=0#

#=>(1+1/x)[-1/2]=0#

#=>1+1/x=0to[because-1/2!=0]#

#=>1/x=-1#

#=>x=-1#

Answer 2 · 2018-08-11T11:55:17

#x=-1#

#1/2*(1+1/x)-2=(1-x)/x#

#1/2*(1+1/x)-2=1/x-1#

#1/2*(1+1/x)=1/x+1#

#1+1/x=2/x+2#

#1/x=-1#

#x=1/(-1)=-1#