Question

Which orbital do these transition metals are filling in? Sc, Ti, V, Cr?

Answer 1

Well, you are filling the `d-"subshell..."`

Explanation:

For scandium, `Z=21`, we got...`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(1)`

For vanadium, `Z=23`, we got...`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(3)`

For titanium, `Z=22`, we got...`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(2)`

For chromium, `Z=Cr`, `Z=24`, we got...`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(4)`

The valence electrons with RESPECT to the atom are the `"d-electrons"`... Upon ionization, we conceive that the `"s-electrons"` are removed first...