What is the equation of the line tangent to #f(x)=x^2-3x # at #x=2#?
1 Answer
Aug 12, 2018
Explanation:
#"to obtain the equation of the tangent we require the "#
#"slope and a point on it"#
#y-b=m(x-a)#
#"slope "=f'(x)" at x = 2"#
#f'(x)=2x-3rArrf'(2)=4-3=1#
#f(2)=4-6=-2rArr(a,b)=(2,-2)#
#y+2=x-2#
#y=x-4larrcolor(red)"equation of tangent"#
