How do you solve #-2( x + 4) > 6x - 4#?
1 Answer
Aug 14, 2018
Explanation:
#"distribute bracket on left side"#
#-2x-8>6x-4#
#"subtract "6x" from both sides"#
#-2x-6x-8> -4#
#-8x-8> -4#
#"add 8 to both sides"#
#-8x>4#
#"divide both sides by "-8#
#color(blue)"reversing the symbol as a consequence"#
#x< -1/2#
#x in(-oo,-1/2)larrcolor(blue)"in interval notation"#
