# 0.345 moles of CH_4 is placed in a 15.0 L container at a temperature of 25.2°C. What is the pressure in atm exerted by the gas?

Approx. $\frac{1}{2} \cdot \text{atm}$
$P = \frac{n R T}{V}$ $=$ $\frac{0.345 \cdot m o l \times 0.00821 \cdot L \cdot a t m \cdot {K}^{-} 1 \cdot m o {l}^{-} 1 \times 298.2 \cdot K}{15.0 \cdot L}$
$=$ ??*atm