Question

1+ tan(x/2)/1-tan (x/2).what is the process to solve it?

Answer 1

`(1+ tan(x/2))/(1-tan (x/2))=tan(pi/4+x/2)`

Explanation:

`(1+ tan(x/2))/(1-tan (x/2))` and as `tan(pi/4)=1`, we can write it as

= `(tan(pi/4)+ tan(x/2))/(1-tan(pi/4)tan (x/2))`

But as `tan(A+B)=(tanA+tanB)/(1-tanAtanB)`

this is `tan(pi/4+x/2)`

where `A=pi/4` and `B=x/2`