# 105 g water is saturated with ammonia gas to form a solution of density 1.0g / mL and containing 30g ammonia, by mass. What is the volume of solution formed?

Aug 1, 2017

Well, clearly you have a solution mass of $135 \cdot g$.....agreed?

#### Explanation:

And you have specified the density, ${\rho}_{\text{solution}} = 1.0 \cdot g \cdot m {L}^{-} 1$.

And since $\rho = \text{Mass of solution"/"Volume of solution}$, by definition.......

$\frac{\text{Volume of solution"="Mass of solution}}{\rho} = \frac{135 \cdot \cancel{g}}{1.0 \cdot \cancel{g} \cdot m {L}^{-} 1}$

$= 135 \cdot \frac{1}{m {L}^{-} 1} = 135 \cdot \frac{1}{\frac{1}{m L}} = 135 \cdot m L$....

$\left[N {H}_{3}\right] = \text{Moles of ammonia"/"Volume of solution} = \frac{\frac{30 \cdot g}{17.03 \cdot g \cdot m o {l}^{-} 1}}{0.135 \cdot L} = 13.0 \cdot m o l \cdot {L}^{-} 1.$