# 11. 135 g of aluminum (initially at "400"^("o")"C") are mixed with an unknown mass of water (initially at "25"^("o")"C"). When thermal equilibrium is reached, the system has a temperature of "80"^("o")"C". Find the mass of the water?

Apr 7, 2015

$- {Q}_{A l} = {Q}_{{H}_{2} O}$ where $Q = m c \Delta T$
-m_"Al"·c_"Al"·(T_f-T_i)=m_(H_2O)·c_(H_2O)(T_f-T_i)
$- \left(135 g\right) \left(0.9 J {g}^{- 1} {C}^{- 1}\right) \left({80}^{o} C - {400}^{o} C\right) = m \left(4.184 J {g}^{- 1} {C}^{- 1}\right) \left({80}^{o} C - {25}^{o} C\right)$