# 128.3 grams of methane is equal to how many moles of methane?

##### 1 Answer
Feb 8, 2017

About $8.0 \cdot m o l$

#### Explanation:

$\text{Number of moles}$ $=$ $\text{Mass"/"Molar mass}$.

And thus we get the quotient:

$\frac{128.3 \cdot \cancel{g}}{16.04 \cdot \cancel{g} \cdot m o {l}^{-} 1} = 8.0 \cdot \text{moles of methane} .$

Note that the expression is dimensionally consistent, we wanted an answer in moles, and the quotients gives, $\frac{1}{m o {l}^{-} 1} = \frac{1}{\frac{1}{m o l}} = m o l$ as required.

Under standard conditions of pressure and temperature, what volume would this molar quantity of methane occupy?